ENERGY SOURCES
These sources of energy are going to be cheap or with no prics apart from the starting materials and their maintenance which is going to be very simple. The more important points about these sources of energy are that it is unlimited, permanent, efficient and 100% clean. The most important difference of these sources from the sources which humanity used before or still using nowadays (wood, coal, oil fuels, nuclear fuels, etc.) is that all these materials needed to be burned or reacted to enable us to get energy out of iL These new sources of energy are based on transferring the energy from one place to another without burning or destroying anything.
The main objectives of this invention are using the differences in the temperatures between day and night, the differences in temperatures from one place to another, the differences in the temperatures between two baths (for example one bath is warmed by means of absorbing the sun radiation and the other bath is cooled by means of evaporation), or the difference in temperatures between deep underground water and the atmosphere temperatures. Generally speaking any two ranges of temperatures which can be found and between which we can work, can be used as a source of energy via the difference of the pressure of a suitable fluid at the two different temperatures.
From theoretical point of view we can use any substance which has different pressures at different temperatures. Practically it will be unwise to use any corrosive materials (such as acids, alkalis or any substances wnich may react with or damage the apparatus in use by this technique), any explosive materiais, any extreme poisonous materials (such as carbon monoxide (CO), hydrogen cyantαe (HCN)). Any other materials which have a vital effect on the life of the people or the environment in case of an accident or leak in the aDDaratus ADart from that all the materials whicn are suitable as a pressure source can be used as long as they are used by the right and well prepared skills.
THEORY NUMBER ONE
The difference in the vapour pressures of a fluid (gas, liquid, solution, solvent, etc.) at two different temperatures is the driving force, which is going to supply our needs of energy.
The main purpose of the next models, examples and techniques is to explain how we can make the vapour pressure of fluids a useful tool. All the specifications of the materials and apparatus are going to be set and at the nght time using the best available skills and technology, to achieve the best efficiency with the highest safety possible.
MODEL NUMBER ONE
Figure-1 theory-1 (page 32) shows a schematic diagram for a vertical power supply unit using the vapour pressure of fluid.
1- Injecting vapour pressure source. 2- Pressure gauge.
3- Vapour pressure source traps (Heat 4- Flexible pressure tube. exchanger).
5- Elastic or rubber bag. 6- Pressure reservoir.
7- Grid. 8- Pressure tube.
9- One way valve. 10- Reservoir A.
11 - Flow controller. 12- Turbines Area.
13- Reservoir B . 14- One way valve.
If we presume that we are going to build a power supply unit in a city called X, using the vapour pressure phenomena of the fluids.
The most important factor in our project is the temperature. From the meteorological history of the X city, the average day temperatures is 25 °C (298 K), and the average night temperatures is 15 °C (28B K). For the sake of the expenment we also assume that this city is nearby hills with different heights.
The power supply unit consists of a large pressure water reservoir 6 (main reservoir), with the capability of standing the pressure, which is going to be under from the vapour pressure source and the water column 8 that is coming from reservoirs A 10 and B 13, and with a capacity that capable of continuing running the system in the period of what I call, the Breathing In Period (when the water column between the mam reservoir 6 and reservoir B 13 has a pressure higher than the pressure of the vapour pressure source). The pressure reservoir 6 is fitted with an elastic or a rubber bag 5 which can expand easily to replace the water, when the system is in the period of what I call, the Breathing Out Period (when the vapour pressure source has a pressure higher than the pressure of the water column between reservoir A 10 and the main reservoir 6). The rubber bag 5 in the mam reservoir 6 is connected via a flexible pressure tube 4 to a group of traps 3 (the traps are different in their size and number, depending on the kind and the quantity of the vapour pressure source (fluid)). The mam purposes of the traps 3 (heat exchangers) are to work as a reservoir for the vapour pressure source in the breathing in period, and to enable the vapour pressure source from exchanging the temperature with the surrounding bath in a suitable time. The vapour pressure traps are fitted with a valve 1 (for injecting in and taking out the vapour pressure source safely and easily), and with a gauge 2 or more to monitor the pressure inside the system.
The main reservoir 6 is connected to reservoirs A 10 and B 13 via a pressure tube 8 (mam tube), which is caoable of standing the pressure when it is full of water, ana with suitable diameter to tet the water flow up ana down freely and easily as a function of the pressure, which the main reservoir 6 is going to be under The ressure tube 8 is fitted with two one wa valves 14 9. The first valve
14 is fitted to the connection between the main tube 8 and reservoir B 13 (this valve 14 permits the fluid (water) to flow only from reservoir B 13 to the main reservoir 6). The second valve 9 is fitted to the main tube 8 in the level between reservoirs A 10 and B 13. (this valve 9 permits the fluid to flow up only, from the main reservoir 6 to reservoir A 10). In the area of the pressure tube (between the main reservoir 6 and reservoir B 13) the fluid can flow in both directions.
Reservoirs A 10 and B 13 each has at least twice the volume or capacity of the main reservoir.
On the nearest point on the top of reservoir B 13, the unit will equipped with turbine(s) 12 or any suitable apparatus, that is capable of transferring the potential energy of the water (fluid), which is coming down from reservoir A 10, to a useful work (e.g. generating electricity).
For the sake of the experiment we presume that we have all the facilities and the specific details we need to build the power unit as outlined in fιgure-1 theory-1.
From the meteorological history and geographical position of the X city, I am going to suggest the use of carbon dioxide as a vapour pressure source.
From the available information about carbon dioxide vapour pressure as a function of temperatures (Table-1b theory-1), we see that at a temperature of 15 °C (288 K), wβ need a column of water with a height of about 518 metre, to balance the carbon dioxide vapour pressure. Also at a temperature of 25 °C (298 K), we need a column of water with a height of about 656 metre, to balance carbon dioxide vapour pressure.
Now we have all the basic information we need about the positions of the reservoirs (the main reservoir 6, reservoir A 10 and reservoir B 13).
Near the hills we set or build the main reservoir. On a place higher than the main reservoir 6 with about 544 metre we set or build reservoir B 13. On the nearest position close to reservoir B 13, and on place higher than the main reservoir 6 with about 626 meter we set or build reservoir A 10.
For the sake of the explanation, we presume that the power unit have been built in a similar manner as in figure-1 theory-1. The main reservoir 6, the pressure tube 8 and half of reservoir B 13, all are filled with water (we have to make sure that no air is left in the main reservoir 6 or in the pressure tube 8 which is connecting the main reservoir 6 with reservoirs A 10 and B 13).
Now everything is in place and from a simple calculations, or from available tables we presume that for every 500 litre of water we need to push from the main reservoir 6 to reservoir A 10 we need between 60 - 80 Kg cartoon dioxide.
We are at the last stage, where we are ready to start injecting carbon dioxide. Before injecting the pressure source (here carbon dioxide), we thoroughly evacuate the vapour pressure traps 3, the flexible pressure tube 4 and the connection between carbon dioxide main injecting source and the injecting vapour pressure source valve 1. In this practical example, it will be a good idea to inject carbon dioxide during the day and when the temperature is 25°C or higher. We have to make sure that the inside surface of the rubber bag 5 temperature inside the main reservoir 6 is similar or higher than the temperature outside to avoid pressure failure.
Now we start injecting carbon dioxide slowly, and may be on stages, and on more than one day, to make sure that all the volume occupied by our vapour pressure source have a homogenous temperature similar to the vapour pressure source traps 3 and its bath (here the bath is the atmosphere). We continue injecting carbon dioxide until about 2/3 of the water in the main reservoir 6 gets transferred to reservoir A 10 (The grid 7 was made to protect the rubber bag). Now everything is finished, where we are going to leave everything for nature (the differences in the temperatures between day and night) to piay its role in dnving our system between the two stages of Breathing Out Period during the day, where the carbon αiαxfde , aosoros heat from the surrounding environment (here the atmosphere), and pusnes the water up against the earth's gravity from
the mam reservoir 6 to reservoir A 10, and Breathing in Period during the night, where the surrounding environment absorbs some of the carbon dioxide's heat and as result of this the earth's gravity pulls the water down from reservoir B 13 to refill the main reservoir 6. On the next day the temperature rises again and the breathing out period gets restarted, the night comes and the temperature falls down and the breathing in period restarted again and so on.
The only thing still for us to do is to adjust (manually or automatically) the rate of the water flow 11 from reservoir A 10, and which is going to rotate turbιne(s) 12, and come down into reservoir B 13, where it will be ready for the breathing in period.
So we have now a power supply mechanism, producing a free energy. The electricity which is going to be generated from this technique is unlimited (depends only on how big the unit is and on the number of units we are going to build).
MODEL NUMBER TWO
Figure-2 theory-1 (page 33) shows schematic diagram for a vertical power supply unit using the vapour pressure of fluid.
1- Injecting vapour pressure source. 2- Pressure gauge.
3- Vapour pressure source traps (Heat 4- Flexible pressure tube. exchanger).
5- Elastic or rubber bag. 6- Pressure reservoir.
7- Hydraulic cylinder. 8- Piston.
9- Piston rod. 10- Load.
II- Gears. 12- Chains moving up and down to rotate the gears. 13- Reservoir B. 14- One way valve.
To use a fluid with a high vapour pressure at the working temperatures such as carbon dioxide, I'm going to suggest another model as it is explained in fιgure-2 theory-1. This model is basically consists of :-
1- Vapour pressure traps 3 with suitable sizes and specifications and purposes similar to the model explained before.
2- A pressure reservoir 6 with a suitable capacity and has a rubber bag 5 connected to the traps via a flexible pressure tube 4 as explained before.
3- A hydraulic cylinder 7 with a capacity of about 2/3 the capacity of the pressure fluid reservoir 6, which is connected to in a way similar to fιgure-2 theory-1 The hydraulic cylinder 7 is set in a vertical position and designed in a way such that, it becomes capable of transferring the mechanical force to an electric one (for examDie by means of rotating cnains, gears, flying wneels etc.)
4- By doing simple calculations wβ can know how, much load 10 we need to balance the vapour pressure at its breathing in period.
5- If we presume that the power unit (s) is built and set in a similar manner to that shown in figure-2 theory-1, then we are ready to operate the system.
The unit we built has a hydraulic cylinder 7 with a capacity of 314.16 litre (20 cm in diameter and 1000 cm in height), a pressure reservoir 6 with a capacity of about 470 litre, a number of vapour pressure traps 3 capable of exchanging heat with the surrounding environment in a short time (say one hour) and a capacity of holding enough quantity of, say, butane (CH3C2H4CH3) which can give 1/4 more weight than that we need when our system is in the breathing out period (This is more than the quantity needed to reach the vapour pressure at the higher temperature).
For the sake of explanation we assume that we are still in X city. At 15 °C (288 K) we need about 1.8 Kg/cm2 to balance the vapour pressure of butane (tabie-2 theory-1 ), and for more precautions we are going to put 628 Kg load 10 to push down against the vapour pressure of butane.
At temperature of 25 °C or higher we start injecting butane pushing up the piston 8 and its load 10 until the piston reaches its maximum height. Now the system has been completed and we are going to leave it for nature (the differences between day and night temperatures) to operate like model number one, or we can make it working between two baths totally or partially created by us. This system has the ability to work under a wide range of temperatures using the same source of vapour pressure (just by adjusting the value of the load 10).
MODEL NUMBER THREE
Figure-3 theory-1 (page 34) shows schematic diagram for a horizontal power supply unit using the vapour pressure of fluid.
1- Injecting vapour pressure source 2- Pressure gauge.
valve.
3- Vapour pressure source traps (Heat 4- Flexible pressure tube.
exchanger).
5- Elastic or rubber bag. 6- Pressure reservoir.
7- Hydraulic fluid. 8- Two identical hydraulic cylinders.
9- Piston 10- Piston rod.
II- Flexible arms to rotate the chain in 12- Chain to rotate electric one direction. generators.
13- Base.
This model is almost identical to model number two except that it is built horizoritally and instead of balancing the vapour pressure with a load, here we are going to build the power unit in similar manner to fιgure-3 theory-1 , where each hydraulic cylinder is balanced with another identical hydraulic cylinder. The two identical hydraulic cylinders 8 are both under the effect of two opposite forces having the same value at the same temperature (as a result of using the same quantity of the same vapour pressure source). This system starts working when the vapour pressure traps connected to the hydraulic cylinders are under different temperatures.
When this system is completed, we inject the same quantity of the same vapour pressure source (in a similar manner to model number two), in eacn side of the unit. We can't leave this system to operate under the effect of the nature
alone, but it can be operated manually or automatically by maxing one half of the unit in the breathing in penod, and at the same time the other half must be in the breathing out period. This can be done by creating one or two baths with each bath temperature is different from the other, and switching our vapour pressure traps between them alternatively.
As another example of endless vapour pressure sources, in model number three, I'm going to suggest using propane (C3H8) (Table-3 theory-1).
MODEL NUMBER FOUR
Figure-4 theory-1 (page 35) shows schematic diagram for a horizontal power supply unit using the vapour pressure of fluid.
1 - Injecting vapour pressure valve. 2- Pressure gauge.
3- Vapour pressure source traps (Heat exchanger). 4- Flexible pressure tube.
5- Elastic or rubber bag. 6- Pressure reservoir.
7- Hydraulic fluid. 8-Turbines.
This model (fιgure-4 theory-1 ) works almost in the same way as model number three, except that here, the hydraulic cylinders are replaced by hydraulic motors) 8, which is operate by the flow of hydraulic fluid 7, that runs between two large pressure reservoirs 6. The two pressure reservoirs 6 are under the effect of two different vapour pressure forces, coming from using the same quantity of the same vapour pressure source. The difference between the two forces comes from the difference of the temperatures, wnich is the vapour pressure sources are going to be under.
MODEL NUMBER FlVE
Figure-5a theory-1 (page 36) shows schematic diagram for a vertical power supply unit using the vapour pressure of water.
A Vapour pressure cells.
B A column of vapour pressure cells.
1 - Water inlet tube. 2- Starting cell (Base cell).
3- Vapour pressure pushing cell. 4- Receiving cell.
5- One way vaive. 6- Carrying tube.
7- Building up cells. 8- Balancing atmospheric pressure.
9- Final Receiving Cell. 10- To receiving main Reservoir.
11- Air bleeding tap.
The basic unit of this model (figure 5.a) is built of a vertical column of vapour pressure cells. The unit consists of a starting cell 2 (base cell) and the build up cells 7. The build up cells consist of vapour pressure pushing cells 3 and receiving cells 4, (the vapour pressure pushing cells 3 are similar to the base cell 2 except that, each vapour pressure pushing cell 3 is receiving its water from a receiving cell 4 built on the top of it directly, while the base cell 2 receives its water from another source outside the unit 1).
For the sake of explanation again we presume that wβ build blocks of columns of vapour pressure cells B (figure 5.a), each block consists of columns which have cells with the same height (suitable for the vapour pressure source which we are going to use and the range of the available temperatures), and with suitable diameter (s) to achieve the hignest efficiency possible.
a- If we are going to use the water itself as a source of the vapour pressure, then during the night (low temperature period). we connect the starting
cell 2 to the water source (e.g. the main reservoir). By bleeding any air trapped inside the starting cell 2, this cell will be filled with water. When the next day comes and the temperature starts to rise, the water vapour pressure starts building up, but it can't push back to the water source as a result of the one way valve 5. The only chance for the pressure inside the starting cell 2 (base cell), to balance itself with the atmospheric pressure is by pushing the water up (via the carrying tube 6 connecting between near the bottom of the base cell 2 and near the top of the next receiving cell 4), to the next receiving cell 4. Next night (the low temperature penod), the base cell 2 will be refilled with water from the main source, and after bleeding the air from the pushing cell 3 under the first receiving cell 4, the water comes down and fill the pushing cell 3 with water. Next day (the high temperature period), the pushing cell will be ready to repeat the same story with the base cell 2, by pushing its water up to the next receiving cell 4. This cycle is going to repeat itself and when the water reaches the height we need, it will end to a receiving reservoir 10 which collect the water from the rest of the columns and blocks, which will operate in a similar manner to the example unit The water which is collected going to be used as a force source in a similar manner to the water collected in reservoir A (figure-1 theory-1 ) model number one and recollected into main reservoir (here the main reservoir is not pressure reservoir) for reuse.
Figure-5b theory-1 (page 37) shows schematic diagram for a vertical power supply unit using the vapour pressure of fluid.
1- Injecting vapour pressure valve. 2- Pressure gauge.
3- Vapour pressure source traps (Heat exchanger). 4- Elastic or rubber bag.
5- Water or fluid inlet tube. 6- One way valve.
7- Starting cell. 8- Receiving cell
9- Vapour pressure pushing cell. 10- Carrying tube.
11- Final Receiving Cell. 12- To receiving main Reservoir. 13- Air bleeding tap. b- If we are going to use another suitable vapour pressure source (e.g. ethanol, acetone, petroleum spirits, etc.), the only change we may need to do (apart from the rubber bags 4, which are going to be fitted to the top of each pushing cell, and contain or connected to the vapour pressure source -figure 5b-) is to use another cells with different heights suitable for the chosen vapour pressure source. Apart from that it will be in complete similarity, to the way and how the two designs (figures 5a and b) are operating.
MODEL NUMBER SIX
Figure-6a theory-1 (page 3S) shows schematic diagram for a step power supply unit using the vapour pressure of water.
1- Water inlet tube. 2- Starting cell (Base cell).
3- Receiving cell. 4- Vapour pressure pushing cell.
5- Air bleeding tap. 6- Balancing atmospheric pressure.
7- To receiving main Reservoir.
Figure-6b theory-1 (page 39) shows schematic diagram for a step power supply unit using the vapour pressure of fluid. - Water or fluid inlet tube. 2- Starting cell.
- Vapour pressure source traps (Heat exchanger). 4- Injecting vapour pressure valve.- Pressure gauge. 6- Elastic or rubber bag.
- One way valve. 8- Receiving ceil
- To receiving main Reservoir. 10- Balancing atmospheric pressure.
This model is almost identical to model number five in using the water vapour pressure (figure 6a) or any other suitable vapour pressure (figure 6b) as a force to push the water up against the earth gravity. The only major difference of this model is that, here we use what 1 call step cells, wnere instead of one column (model number five), here (model number six) we use two columns sided to each other, and with different cells opposite to each other (each pushing cell sided with a receiving cell except that the starting cell is sided with a pushing cell). The main purpose of using this model is to reduce the pressure that is needed to push
agamst (especially when, using the water Itself as a vapour pressure source). In model number five we see that for our system to work, the water is needed to push up through (our cells, while in mode. number six, the water is needed only three cells to push up through, in order to make this model working, and this will be very useful specially at low temperatures, where the water vapour pressure is very limited (Table-4 theory-1).
The only comment I'm going to make about the last two models is this :- If we succeed to build units (something like models 5 and 6, figures 5.a and 6.a), and based on using the differences of the water vapour pressure between day and night, as a driving force to push the water rtself up against the earth's gravity, then this means we will get the ability to take an ocean of water up to the sky and lefs imagine the benefit of that.
THEORY NUMBER TWO
The more suitable difference between the volume which is occupied by a suitable fluid (while its in the liquid phase) and the volume which is occupied by the same fluid (while its in the gas phase), below and above its critical temperature, is going to be the more efficient force that is going to satisfy our needs of energy.
As it has been explained in theory number one, the vapour pressure phenomena gave us unlimited, permanent and a clean source of energy and left us with three main disadvantages:
a- Restricted positions for the used reservoirs depending on the used vapour pressure source and the available temperatures in the area of building. b- Limited effective height depending on the used vapour pressure source and the available temperatures in the area of building.
c- Restncted heights for the used reservoirs depending on the used vapour pressure source and the available temperatures in the area of building
The three mentioned disadvantages are going to have a great impact on the cost of building and the efficiency of the produced energy.
Using theory number two is going to keep all the advantages of theory number one and avoid all the disadvantages of the same theory.
Figure-2 theory-2 (page 40) shows schematic diagram for a vertical power supply unit using the volumes differences of fluids below and above their critical temperatures
1- Pressure source traps (Heat exchangers). 2- Pressure reservoirs.
3- Pressure tube. 4- One way valve..
5- Reservoιr(s) A. 6- Flow controller.
7- Turbines Area. 8- Reservoir(s) B.
9- One way valve. 10- Total height
11- Critical height. 12- Effective height.
13- Heights area. 14- Balancing outside pressure.
Via the theoretical study' to the relation between the height in metres, the produced energy in joules, and the quantity of the used water in kilograms, while using a certain and a fixed weight of a fluid, that is a suitable to the temperatures that available in the area of building (figure-1 theory-2). It has been concluded that it is so important to choose suitable positions for :- The pressure reservoir(s) 1, reservoirs) A 5, and reservoir(s) B 8 (figure -2 theory-2]. In this study when the effective height 12 (the space between reservoir(s) A 5 and reservoir(s) B 8, or more precisely the height difference between the top level of the water in the reservoir(s) A 5 and the turbine(s) 7) was four metres, the energy (potential energy) that can be got is 588.35 joule, for every 15.009 Kg water used. And when the effective height was 1902 metres, the energy that can be get is 56142.48 joule, for only every 3.012 Kg water used.
And from this we find that, in the same time in which the energy was increased from 588.35 to 56142.48 joule, the water quantity was decreased from 15.009 to 3.012 Kg (20%).
______________________________
'The study was used as a general indicator only, where we presumed that the fluids behave as an ideal gas in the temperatures above, its critical temperature.
Therefore, by choosing the suitable effective height 12, the energy was increased 95.42 times, while the water needed to achieve this was only 20% from the water used when the height was four metres. And as a result of this; the energy achieved by one litre of water was increased from 39.2 to 18639.6 joule (475.5 times). All this improvement in the energy efficiency was produced from using a certain and a fixed weight of the fluid.
Fιgures-3,4 theory-2 show the importance of knowing the fluids density2 (pressure sources) while they are in the liquid phase, and their changes as a function of temperatures, which are going to be available in the area of building specially before reaching the critical temperature (or more correctly the critical points Ipressure, temperature and cntical volume|).
Generally speaking by doing more accurate theoretical and experimental studies we will be able to get more accurate information about the design and the volume of the traps 1 (heat exchangers), quantity of the pressure sources (fluids) needed for the required energy and pointing the most reliable positions for the reservoirs, to achieve the best efficiency possible while using a certain and a fixed weight of the fluid (s) concerned.
__________________________
2lt's very likely that the clear changes in the fluid density (the pressure source), near it's critical temperature is going to play a very important rule in torming the energy (as a result ot pusning the water against the earth's gravity).
[Figure-1 Theory-2] The relation between height in metres, the used water in grams and potential energy in joule, when a certain and a fixed weight of fluid has been used.
/
[Figure-4 Theory-2] The relation between height in metres, the used water [the water pushed by the fluid after its cntical temperature + the water pushed by the fluid before its cntical temperature as a result of the change in the fluid density as a function of temperature increasing (D)] in grams and the potential energy in joules, when a certain and a fixed weight of fluid has been used.
APPENDIX A
SUPPORTING DISCUSSION
From the Vapour Pressure Theory (Theory No-1 ), and the work below and above the critical paints of suitable fluids (Theory No-2). We are able to overcome many disadvantages, that are always combined with heat engines like:-
1- The limitation of the energy out put (the recovered energy).
This comes as a result of:- a- The energy consumed in the pumping systems,
b- The energy consumed in the heating and cooling systems, if we look at figure-1 theory-1 and figure-2 theory-2 we see that-
As a result of the water pressure, that is coming down from reservoirs B 13 and 8, and as a result of using the explained traps 3 and 1 (heat exchanger), with the right specifications and the right fluids (pressure sources), the heat will flow naturally from the fluid inside the traps to the surrounding, and the fluid will be liquefied, and by this, the job of the cooling and pumping systems will be achieved naturally dunng the low temperature period (Breathing In Period).
During the high temperature period (Breathing Out Period), the heat will flow naturally from the surrounding to the liquid fluid inside the traps, transferring it gradually to a less condensed state, and by this, the pressure will build up and the water in the main reservoirs 6 and 2 will be pushed up to a level with higher potential energy (reservoirs 10 and 5) and the job of heating (warming) systems will be achieved naturally.
2- The turbines limited driving force
To explain this, it will be more helpful if we refer to fιgure-1D, which outlined a good simple example about this kind of existing energy sources.
The two main forces that the turbine(s) will be under (e.g. Ammonia is the fluid) are:-
a- The force coming from the direction of the evaporator, where the ammonia vapour pressure, cannot exceed 147.74 psi (at 24.44°C), at its ideal conditions.
b- The force coming from the direction of the condenser, where the ammonia vapour pressure, cannot be less than 78.87 psi (at 5.56°C), at its ideal conditions.
And as a result of these two pressures, the turbine (s) driving force cannot exceed the force, that is coming from the net pressure of the two opposite mentioned pressures, which is 68.87 psi at its ideal conditions.
From theory-2 (figure-2), the turbιne (s) 7 will be under only one driving force, that is coming from the effective height 12 (e.g. when the effective height 12 was 1902 metre, the net pressure will be about 2700 psi).
3- Camot Theorem Defect
It is a well known fact, via the famous Camot Theorem, that the efficiency of heat engines is The efficiency depends only on the two
temperatures (the higher temperature TH, and the lower temperature Tc) and not on the working substances(e.g. fluids). As a result of this famous theorem, the overall heat engines efficiency will be very limited (Table-1D)
By understanding the basic simple facts, the new invention built on, we will find that the famous Camot Theorem is not applicable in our case. How ?
The liquid fluid inside the smallest single unit (cell) which is the heat exchanger (traps) built from, (naturally is going to have the same temperature as its
medium). So during the high temperature period (e.g. during day), it will start absorbing heat through its well conductive boundary, from the surrounding increased temperature, and because the right chosen fluid (in its confine volume and at the available temperatures) starts to build up a pressure higher than the pressure of the water column (8 and 3), which is coming from the pressure tube connecting between the main pressure reservoirs (6 and 2), and reservoirs A (10 and 5) (fιgure-1 theory-1 and fιgure-2 theory-2). So that the water will flow from the main reservoirs (6 and 2) to the reservoirs A (5 and 10), until all the liquid fluid gets transferred to a less condensed state with pressure and temperature in equilibrium with the pressure and temperature that is under.
During the low temperature period (e.g. during night), the pressure of the water column, coming from the pressure tube 3 connecting between reservoirs B 8, and the main pressure reservoirs 2, has a pressure higher than the critical pressure (critical height 11 ) (figure-2 theory-2) of the concerned fluid. So that the surrounding starts absorbing the extra heat, from the heat exchanger increased temperature, until all the fluid with less condensed state gets transferred to a liquid with a pressure and temperature in equilibrium with the pressure and temperature that is under.
In another words this kind of heat exchangers, functioning naturally with 100% efficiency as long as they are under the conditions, they are designed for, and the overall efficiency will be calculated from the turbines efficiency only.